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6m^2=72+24m
We move all terms to the left:
6m^2-(72+24m)=0
We add all the numbers together, and all the variables
6m^2-(24m+72)=0
We get rid of parentheses
6m^2-24m-72=0
a = 6; b = -24; c = -72;
Δ = b2-4ac
Δ = -242-4·6·(-72)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-48}{2*6}=\frac{-24}{12} =-2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+48}{2*6}=\frac{72}{12} =6 $
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